Differentiate lmplicitly x^2y^2-3xy+4xy^3=4

1 answer

x^2y^2-3xy+4xy^3=4
(x^2)(2y)(dy/dx) + 2x(y^2) - 3x(dy/dx) - 3y + 4x(3y^2)(dy/dx) + 4y^3 = 0
dy/dx(2x^2 y) - 3x + 12x y^2) = 3y - 2x(y^2) - 4y^3

finish it up
Similar Questions
  1. 1. differentiate cos(3/x)2. differentiate sin(4/x) 3. differentiate 3/{sin(3x+pi)} 4. differentiate pxsin(q/x)where p and q are
    1. answers icon 0 answers
    1. answers icon 1 answer
  2. 1) solve:e^x(x^2-4)=0e^x=0 and then (x+2)(x-2) so x=2, -2 2) differentiate: y=ln(6x^2 - 3x + 1) 1/(6x^2 - 3x + 1) * 12x-3 3)
    1. answers icon 4 answers
  3. I'm having problems with this one. Can't get the right answer.Differentiate the following using the chain rule. f(x) =
    1. answers icon 1 answer
more similar questions