Differentiate lmplicitly x^2y^2-3xy+4xy^3=4

Answer 1

x^2y^2-3xy+4xy^3=4
(x^2)(2y)(dy/dx) + 2x(y^2) - 3x(dy/dx) - 3y + 4x(3y^2)(dy/dx) + 4y^3 = 0
dy/dx(2x^2 y) - 3x + 12x y^2) = 3y - 2x(y^2) - 4y^3

finish it up