Possible derivation:
d/dx(f(x)) = d/dx(log(x) csc(x))
The derivative of f(x) is f'(x):
f'(x) = d/dx(log(x) csc(x))
Use the product rule, d/dx(u v) = v ( du)/( dx)+u ( dv)/( dx), where u =csc(x) and v = log(x):
f'(x) = log(x) (d/dx(csc(x)))+csc(x) (d/dx(log(x)))
The derivative of log(x) is 1/x:
f'(x) = log(x) (d/dx(csc(x)))+(csc(x))/x
The derivative of csc(x) is -cot(x) csc(x):
Answer
| f'(x) = (csc(x))/x+log(x) (-(cot(x) csc(x)))
Differentiate f(x) = ln(x)/sin(x)
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