is this arccos (2x)?
or do you mean 1/(cos 2x)
Differentiate.
cos^-1 2x
2 answers
I think we can assume arccos.
If so, then recall that d/dx (arccos(u)) = -1/√(1-u^2) du/dx
Now just plug and chug.
If so, then recall that d/dx (arccos(u)) = -1/√(1-u^2) du/dx
Now just plug and chug.