looks like a continuation of ...
http://www.jiskha.com/display.cgi?id=1455252502
now you changed it to
V^3-2v√v/v
which clearly reduces to
V^3-2√v
and the derivative is even easier
f(v) = v^3 - 2v^(1/2)
f ' (v) = 3v^2 - v^(-1/2)
or
3v^2 - 1/√v
Differeniate
V^3-2v√v/v
I used the quotient rule
(v)(v^3-2v√v)' -(v^3-2v√v)(v)' /(v)
The answer is 2v-1-1
I got this far but then I don't know what to do further
2v^3-2v^1/2+2v√v/(v)^2
2 answers
unless she really meant
(v^3-2v√v)/v
which is just
v^2 - 2√v
and integrates to
v^3/3 - 4v√v/3
+c
(v^3-2v√v)/v
which is just
v^2 - 2√v
and integrates to
v^3/3 - 4v√v/3
+c