f(v) = v^3 - 2v^(3/2)
f ' (x) = 3v^2 - 3v^(1/2)
= 3v^2 - 3/√v
Why would you think of using the quotient rule ? There is no division .
Differeniate
V^3-2v√v
I used the quotient rule
(v)(v^3-2v√v)' -(v^3-2v√v)(v) /(v)'
The answer is 2v-1-1
I got this far but then I don't know what to do further
2v^3-2v^1/2+2v√v/(v)^2
3 answers
Idon't why my phone didn't put the end part the problem is v^3-2v√v/v
Idon't why my phone didn't put the end part the problem is v^3-2v√v/v