1/(Y+5) - 1/Y =1/10 <----- you had 10
LCD is y(y+5)
y - (y+5) = y(y+5)/10
-50 = y^2 + 5y
y^2 + 5y + 50 = 0
no real solution.
Difference of two ninbers is 5 and difference of thier reciprocal is 1/10 find the numbers.
Answer:
X-Y=5
X=Y+5
1/X - 1/Y = 10
1/Y+5 - 1/Y =10
LCM
....
3 answers
1/y - 1/(y+5) = 1/10
y = 5
check:
1/5 - 1/10 = 1/10
y = 5
check:
1/5 - 1/10 = 1/10
Given that
x-y=5
x=5+y(say-----equation 1)
Now clearly 1/x is less than 1/y because denominator of y is greater than x
therefore
1/y-1/(y+5)=1/10
on solving we get y=5 or -10
when y=5 then x=10
or when y=-10 then x=-5
x-y=5
x=5+y(say-----equation 1)
Now clearly 1/x is less than 1/y because denominator of y is greater than x
therefore
1/y-1/(y+5)=1/10
on solving we get y=5 or -10
when y=5 then x=10
or when y=-10 then x=-5
1 answer