\[ -\dfrac{6}{7} \times \left(-\dfrac{5}{4}\right) \]

Answer 1

To find the product, we multiply the numerators and denominators separately: \begin{align*}
-\dfrac{6}{7} \times \left(-\dfrac{5}{4}\right) &= \left(-\dfrac{6}{7}\right) \times \left(-\dfrac{5}{4}\right)\\
&= \left(\dfrac{-6 \times -5}{7 \times 4}\right)\\
&= \left(\dfrac{30}{28}\right)\end{align*}We can simplify the fraction $\dfrac{30}{28}$ by dividing both the numerator and the denominator by their greatest common factor, which is $2$: \begin{align*}
\frac{30}{28} &= \frac{2 \times 15}{2 \times 14}\\
&= \frac{15}{14}\end{align*}Therefore, $-\dfrac{6}{7} \times \left(-\dfrac{5}{4}\right) = \boxed{\dfrac{15}{14}}$.

Answer 2

\[ \dfrac{7}{9} \times \left(-\dfrac{5}{7}\right) \]

Answer 3

To find the product, we multiply the numerators and denominators separately: \begin{align*}
\dfrac{7}{9} \times \left(-\dfrac{5}{7}\right) &= \left(\dfrac{7}{9}\right) \times \left(-\dfrac{5}{7}\right)\\
&= \left(\dfrac{7 \times -5}{9 \times 7}\right)\\
&= \left(\dfrac{-35}{63}\right)\end{align*}Since both the numerator and denominator are divisible by 7, we can simplify the fraction: \begin{align*}
\frac{-35}{63} &= \frac{-5 \times 7}{9 \times 7}\\
&= \frac{-5}{9}\end{align*}Thus, $\dfrac{7}{9} \times \left(-\dfrac{5}{7}\right) = \boxed{-\dfrac{5}{9}}$.

Answer 4

wrong...

Answer 5

Apologies for the mistake. Let's try it again.

To multiply these fractions, we multiply the numerators together and the denominators together:

$\dfrac{7}{9} \times \left(-\dfrac{5}{7}\right) = \dfrac{7 \times (-5)}{9 \times 7}$

Simplifying the numerator and denominator:

$\dfrac{7 \times (-5)}{9 \times 7} = \dfrac{-35}{63}$

We can further simplify this fraction by dividing both the numerator and denominator by their greatest common factor, which is 7:

$\dfrac{-35}{63} = \dfrac{-5}{9}$

Therefore, $\dfrac{7}{9} \times \left(-\dfrac{5}{7}\right) = \boxed{-\dfrac{5}{9}}$.