To determine the initial deposit amount prior to the annual increments of the bank account, we can analyze the amounts given in the table.
The amounts after each year are:
- Year 1: $1,080
- Year 2: $1,160
- Year 3: $1,240
From the table, we can see that the account increases by $80 each year. Thus, we can denote the initial deposit as \( P \) and the annual increment as \( D = 80 \).
The amounts for each year can be represented as follows:
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After Year 1: \[ P + (1 \times D) = P + 80 = 1080 \]
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After Year 2: \[ P + (2 \times D) = P + 160 = 1160 \]
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After Year 3: \[ P + (3 \times D) = P + 240 = 1240 \]
Let's solve for \( P \) using the first equation: \[ P + 80 = 1080 \] Subtracting 80 from both sides: \[ P = 1080 - 80 = 1000 \]
Now we can verify using the second and third equations:
For Year 2: \[ 1000 + 160 = 1160 \] This is correct.
For Year 3: \[ 1000 + 240 = 1240 \] This is also correct.
Thus, the initial deposit amount is: \[ \boxed{1000} \]