since you have 2x^2, the parabola opens upward
So, it must have a minimum, which occurs at x = -16/4
Determine without graphing, whether the given quadratic function has a max value or min value and then find the value.
F(x)=2x^2+16x-1
2 answers
f(x)=2(x^2+8x) -1
= 2(x^2+4x+4) -1-8
= 2(x+2)^2 -9
sp as x gets large, either negative or positive, f(x) increases, which means at x=-2 it is a minimum.
= 2(x^2+4x+4) -1-8
= 2(x+2)^2 -9
sp as x gets large, either negative or positive, f(x) increases, which means at x=-2 it is a minimum.
1 answer