determine which of the ordered pairs are solutions to the given equation 3x-2y=12 , (2,-3) (4,-2) (6,3) (5, 15/2)

3 answers

Put x coordinate into equation:

3 x - 2 y = 12

and check y coordinate

1. For x = 2

3 x - 2 y = 3 * 2 - 2 y = 12

6 - 2 y = 12 Subtact 6 to both sides

6 - 2 y - 6 = 12 - 6

- 2 y = 6 Divide both sides by - 2

y = 6 / - 2

y = - 3

x = 2 , y = - 3 True

2. For x = 4

3 x - 2 y = 3 * 4 - 2 y = 12

12 - 2 y = 12 Subtact 12 to both sides

12 - 2 y - 12 = 12 - 12

- 2 y = 0

y = 0

x = 4 , y = 0 False

3. For x = 6

3 x - 2 y = 3 * 6 - 2 y = 12

18 - 2 y = 12 Subtact 18 to both sides

18 - 2 y - 18 = 12 - 18

- 2 y = - 6 Divide both sides by - 2

y = - 6 / - 2

y = 3

x = 6 , y = 3 True

4. For x = 5

3 x - 2 y = 3 * 5 - 2 y = 12

15 - 2 y = 12 Subtact 15 to both sides

15 - 2 y - 15 = 12 - 15

- 2 y = - 3 Divide both sides by - 2

y = - 3 / - 2

y = 3 / 2

x = 5 , y = 3 / 2 False

The ordered pairs are:

( 2 , - 3 ) and ( 6 , 3 )

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