Put x coordinate into equation:
3 x - 2 y = 12
and check y coordinate
1. For x = 2
3 x - 2 y = 3 * 2 - 2 y = 12
6 - 2 y = 12 Subtact 6 to both sides
6 - 2 y - 6 = 12 - 6
- 2 y = 6 Divide both sides by - 2
y = 6 / - 2
y = - 3
x = 2 , y = - 3 True
2. For x = 4
3 x - 2 y = 3 * 4 - 2 y = 12
12 - 2 y = 12 Subtact 12 to both sides
12 - 2 y - 12 = 12 - 12
- 2 y = 0
y = 0
x = 4 , y = 0 False
3. For x = 6
3 x - 2 y = 3 * 6 - 2 y = 12
18 - 2 y = 12 Subtact 18 to both sides
18 - 2 y - 18 = 12 - 18
- 2 y = - 6 Divide both sides by - 2
y = - 6 / - 2
y = 3
x = 6 , y = 3 True
4. For x = 5
3 x - 2 y = 3 * 5 - 2 y = 12
15 - 2 y = 12 Subtact 15 to both sides
15 - 2 y - 15 = 12 - 15
- 2 y = - 3 Divide both sides by - 2
y = - 3 / - 2
y = 3 / 2
x = 5 , y = 3 / 2 False
The ordered pairs are:
( 2 , - 3 ) and ( 6 , 3 )
determine which of the ordered pairs are solutions to the given equation 3x-2y=12 , (2,-3) (4,-2) (6,3) (5, 15/2)
3 answers
:| didnt help
useless