To determine which ordered pair is a solution to the equation \( 3x - 8 = -4y \), we can substitute each pair into the equation and see if it holds true.
-
For the pair \((-1, 1)\): \[ x = -1, \quad y = 1 \] Substituting into the equation: \[ 3(-1) - 8 = -4(1) \] \[ -3 - 8 = -4 \] \[ -11 \neq -4 \quad \text{(not a solution)} \]
-
For the pair \((1, 1)\): \[ x = 1, \quad y = 1 \] Substituting into the equation: \[ 3(1) - 8 = -4(1) \] \[ 3 - 8 = -4 \] \[ -5 \neq -4 \quad \text{(not a solution)} \]
-
For the pair \((0, -2)\): \[ x = 0, \quad y = -2 \] Substituting into the equation: \[ 3(0) - 8 = -4(-2) \] \[ 0 - 8 = 8 \] \[ -8 \neq 8 \quad \text{(not a solution)} \]
-
For the pair \((0, 2)\): \[ x = 0, \quad y = 2 \] Substituting into the equation: \[ 3(0) - 8 = -4(2) \] \[ 0 - 8 = -8 \] \[ -8 = -8 \quad \text{(is a solution)} \]
The only ordered pair that is a solution to the equation \( 3x - 8 = -4y \) is \((0, 2)\).