To determine whether an ordered pair is a solution to an equation, we substitute the values from the ordered pair into the equation and see if the equation holds true.
Let's plug in the values from Option 1: (0, 8)
Our equation is 8 - 2y = 4x^2.
Substituting x = 0 and y = 8 into the equation, we get:
8 - 2(8) = 4(0^2)
8 - 16 = 4(0)
-8 = 0
Since -8 does not equal 0, Option 1: (0, 8) is not a solution to the equation.
Next, let's plug in the values from Option 2: (-1, 2)
Our equation is 8 - 2y = 4x^2.
Substituting x = -1 and y = 2 into the equation, we get:
8 - 2(2) = 4(-1^2)
8 - 4 = 4(1)
4 = 4
Since 4 equals 4, Option 2: (-1, 2) is a solution to the equation.
Lastly, let's plug in the values from Option 3: (4, 0)
Our equation is 8 - 2y = 4x^2.
Substituting x = 4 and y = 0 into the equation, we get:
8 - 2(0) = 4(4^2)
8 - 0 = 4(16)
8 = 64
Since 8 does not equal 64, Option 3: (4, 0) is not a solution to the equation.
Therefore, the ordered pair that is a solution to the equation is Option 2: (-1, 2).
Determine which of the following ordered pairs is a solution to the equation 8−2y=4x^2
.
Option #1: (0,8)
Option #2: (−1,2)
Option #3: (4,0)
1 answer