To determine whether \( x = 3 \) is the solution of the equation \( 2x^2 + 9 - \sqrt{3} = 3 \), we can substitute \( x = 3 \) into the equation and see if both sides are equal.
Let's substitute \( x = 3 \):
\[ 2(3)^2 + 9 - \sqrt{3} = 3 \]
Calculating \( 2(3)^2 \):
\[ 2(9) = 18 \]
So, the left side of the equation becomes:
\[ 18 + 9 - \sqrt{3} = 27 - \sqrt{3} \]
Now we need to check if \( 27 - \sqrt{3} \) equals \( 3 \):
\[ 27 - \sqrt{3} = 3 \]
To isolate \( \sqrt{3} \), we can rearrange this equation:
\[ 27 - 3 = \sqrt{3} \]
This simplifies to:
\[ 24 = \sqrt{3} \]
Since \( 24 \) is not equal to \( \sqrt{3} \), the equation does not hold true.
Thus, \( x = 3 \) is not a solution to the equation \( 2x^2 + 9 - \sqrt{3} = 3 \).
Enter 2 if \( x = 3 \) is not the solution.