To determine whether the values 3 and 4 are solutions to the quadratic equation \( x^2 - 7x + 12 = 0 \), we can substitute each value into the equation and check if it holds true (i.e., equals zero).
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Testing \( x = 3 \): \[ x^2 - 7x + 12 = 3^2 - 7(3) + 12 \] \[ = 9 - 21 + 12 \] \[ = 9 - 21 + 12 = 0 \] So, \( x = 3 \) is a solution.
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Testing \( x = 4 \): \[ x^2 - 7x + 12 = 4^2 - 7(4) + 12 \] \[ = 16 - 28 + 12 \] \[ = 16 - 28 + 12 = 0 \] So, \( x = 4 \) is also a solution.
Since both values satisfy the equation, we conclude that:
C. Both x = 3 and x = 4 are solutions.