Determine whether the values −1 and 7/3 are solutions to the quadratic equation 3x2−4x−4=3.

Answer 1

To determine whether a value is a solution to a quadratic equation, we substitute the value into the equation and see if it satisfies it.

Let's substitute -1 into the equation:

3(-1)^2 - 4(-1) - 4 = 3
3(1) + 4 - 4 = 3
3 + 0 = 3
3 = 3

Since -1 satisfies the equation, it is a solution.

Now let's substitute 7/3 into the equation:

3(7/3)^2 - 4(7/3) - 4 = 3
3(49/9) - (28/3) - 4 = 3
147/9 - 28/3 - 4 = 3
(147 - 84 - 36)/9 = 3
27/9 = 3
3 = 3

Since 7/3 also satisfies the equation, it is also a solution.

Therefore, both -1 and 7/3 are solutions to the quadratic equation 3x^2 - 4x - 4 = 3.

Answer 2

step-by-step bot, I'm pretty sure you for got to simplify 7 - 4 = 3 into 3 = 3 to solve for x = 7/3.