Determine whether the series is convergent or divergent

series symbol n=1 to infinity (n^2/(e^(3n))

2 answers

an+1/an = e^-3 (1 + 2/n + 1/n^2)

that ratio is less than 1, so the series converges.

see

http://www.wolframalpha.com/input/?i=sum+n^2%2Fe^%283n%29
we can't use the ratio test on it. The only thing we know as of now is the integral test.
Similar Questions
    1. answers icon 1 answer
    1. answers icon 0 answers
  1. is this correct?use the integral test to determine if this series is convergent or divergent: the series from n=2 to infinity of
    1. answers icon 0 answers
    1. answers icon 1 answer
more similar questions