For ∫ xdx/(x²-1) from 0 to 2, we have to note that there is a vertical asymptote in the function at x=1, hence divide the range of integration into two parts, namely 0 to 1 and 1 to 2 and integrate accordingly.
If each sub-integral exists and is convergent, the answer is the sum of the two. Otherwise, the original integral is divergent.
Determine whether the integral converges or diverges. Find the value of the integral if it converges.
The integral where b=2 and a=0 (x/x^2-1 dx).
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