about x axis?
for any x is are there equal in magnitude + and - values of y?
y ^2 = x+1
y = +/- sqrt (x+1) so yes but x must be >-1
about y axis?
Nah, this is a parabola opening to the right with as vertex at (-1 , 0)
Determine whether the graph of x=y^2-1 is symmetric with respect to the x-axis, the y-axis, the origin, or has no symmetry.
3 answers
The problem is a quadratic function so that tells you right there that it has symmetry. Now you just have to find where.
Because the problem says x= and not y=
our problem with be rotated to the right
Its rotated to the right because y can be any value whether positive or negative but x will always be a positive number because y is squared.
So now our graph is quadratic and rotated right.(Like a sideways U shape)
Now it says -1 after y^2. This means the graphs shifting down one on the x axis.
With all this being said that means it is symmetrical about the x-axis
Because the problem says x= and not y=
our problem with be rotated to the right
Its rotated to the right because y can be any value whether positive or negative but x will always be a positive number because y is squared.
So now our graph is quadratic and rotated right.(Like a sideways U shape)
Now it says -1 after y^2. This means the graphs shifting down one on the x axis.
With all this being said that means it is symmetrical about the x-axis
Yes, what Mia said :)
2 answers