Determine whether the function f(x)=sin^4xtanx is even or odd

1 answer

To determine whether the function f(x) = sin^4(x)tan(x) is even or odd, we need to check if it satisfies the following properties:

1. Even function property: A function f(x) is even if f(x) = f(-x) for all x in its domain.
2. Odd function property: A function f(x) is odd if f(x) = -f(-x) for all x in its domain.

Let's check both properties for f(x) = sin^4(x)tan(x):

1. Even function property:
f(-x) = sin^4(-x)tan(-x)
Since sin(-x) = -sin(x) and tan(-x) = -tan(x), we have:
f(-x) = (-sin(x))^4 * (-tan(x))
= sin^4(x)tan(x)
Therefore, f(-x) = f(x) for all x in its domain.

2. Odd function property:
-f(-x) = -[sin^4(-x)tan(-x)]
= -[(-sin(x))^4 * (-tan(x))]
= sin^4(x)tan(x)
Therefore, -f(-x) = f(x) for all x in its domain.

Since f(x) = f(-x) and -f(-x) = f(x) for all x in the domain of f(x), the function f(x) = sin^4(x)tan(x) satisfies both the even and odd function properties. While it is possible for a function to be both even and odd (such as f(x) = 0), most functions are neither even nor odd.

Therefore, f(x) = sin^4(x)tan(x) is neither even nor odd.