Question
Determine whether the function below is exponential growth or exponential decay, and find the percentage rate of change.
P(t)= 8.5(0.92)^t
A
Exponential decay; 8.5%
B
Exponential decay; 8%
C
Exponential growth; 8%
D
Exponential growth; 8.5%
P(t)= 8.5(0.92)^t
A
Exponential decay; 8.5%
B
Exponential decay; 8%
C
Exponential growth; 8%
D
Exponential growth; 8.5%
Answers
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Answered by
GPT-4o mini
To determine whether the function \( P(t) = 8.5(0.92)^t \) represents exponential growth or decay, we need to look at the base of the exponent, which is \( 0.92 \).
- If the base is greater than 1, the function represents exponential growth.
- If the base is between 0 and 1, the function represents exponential decay.
Since \( 0.92 < 1 \), the function represents **exponential decay**.
Next, we can find the percentage rate of change. The general form for an exponential decay function is \( P(t) = P_0(1 - r)^t \), where \( r \) is the decay rate.
In our function, we can see that:
\[
P(t) = 8.5(0.92)^t
\]
Here, \( 0.92 = 1 - r \), which implies:
\[
r = 1 - 0.92 = 0.08
\]
To express this as a percentage:
\[
r = 0.08 \times 100\% = 8\%
\]
Putting this all together:
- The function is **exponential decay**.
- The percentage rate of change is **8%**.
Thus, the correct answer is:
**B. Exponential decay; 8%**.
- If the base is greater than 1, the function represents exponential growth.
- If the base is between 0 and 1, the function represents exponential decay.
Since \( 0.92 < 1 \), the function represents **exponential decay**.
Next, we can find the percentage rate of change. The general form for an exponential decay function is \( P(t) = P_0(1 - r)^t \), where \( r \) is the decay rate.
In our function, we can see that:
\[
P(t) = 8.5(0.92)^t
\]
Here, \( 0.92 = 1 - r \), which implies:
\[
r = 1 - 0.92 = 0.08
\]
To express this as a percentage:
\[
r = 0.08 \times 100\% = 8\%
\]
Putting this all together:
- The function is **exponential decay**.
- The percentage rate of change is **8%**.
Thus, the correct answer is:
**B. Exponential decay; 8%**.
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