determine whether left parenthesis negative 3 comma negative 1 right parenthesis


is a solution of the​ system:
3x + y=10
-5 + 2y= 13
Is left parenthesis negative 3 comma negative 1 right parenthesis

a solution of the​ system?

1 answer

To determine if left parenthesis negative 3 comma negative 1 right parenthesis is a solution of the system, we need to substitute x = -3 and y = -1 into each equation and see if both equations are true.

Substituting x = -3 and y = -1 into 3x + y = 10, we get:

3(-3) + (-1) = -9 - 1 = -10

This equation is not true, since -10 does not equal 10. Therefore, left parenthesis negative 3 comma negative 1 right parenthesis is not a solution of the first equation.

Substituting x = -3 and y = -1 into -5 + 2y = 13, we get:

-5 + 2(-1) = -5 - 2 = -7

This equation is also not true, since -7 does not equal 13. Therefore, left parenthesis negative 3 comma negative 1 right parenthesis is not a solution of the second equation.

Since left parenthesis negative 3 comma negative 1 right parenthesis fails to satisfy both equations of the system, it is not a solution of the system.