To determine the zeros of the quadratic function \( y = -5x^2 + 16x \), we will set \( y \) to zero and solve for \( x \):
\[ 0 = -5x^2 + 16x \]
We can factor out \( x \):
\[ 0 = x(-5x + 16) \]
This gives us two factors:
- \( x = 0 \)
- \( -5x + 16 = 0 \)
Solving the second factor:
\[ -5x + 16 = 0 \ 5x = 16 \ x = \frac{16}{5} = 3.2 \]
Thus, the zeros of the function are \( x = 0 \) and \( x = 3.2 \).
In coordinate form, the zeros are:
- \( (0, 0) \)
- \( (3.2, 0) \)
Among the given options, the correct response is:
(3.2, 0).