Question
Determine the zero(s) of the quadratic function y=−5x^2+16x
(1 point)
Responses
(0, 0) and (3.2, 0)
(0, 0) and (3.2, 0)
(-3.2, 0)
(-3.2, 0)
There are no zeros.
There are no zeros.
(0,5) and (0, 16)
(1 point)
Responses
(0, 0) and (3.2, 0)
(0, 0) and (3.2, 0)
(-3.2, 0)
(-3.2, 0)
There are no zeros.
There are no zeros.
(0,5) and (0, 16)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the zeros of the quadratic function \(y = -5x^2 + 16x\), we need to set the equation equal to zero:
\[
-5x^2 + 16x = 0
\]
We can factor out \(x\):
\[
x(-5x + 16) = 0
\]
This gives us two equations to solve:
1. \(x = 0\)
2. \(-5x + 16 = 0\)
Now, let's solve the second equation:
\(-5x + 16 = 0\)
Rearranging gives:
\(-5x = -16\)
Dividing both sides by -5:
\[
x = \frac{16}{5} = 3.2
\]
So the zeros of the function are:
\[
x = 0 \quad \text{and} \quad x = 3.2
\]
In coordinate form, the zeros are (0, 0) and (3.2, 0).
Thus, the correct response is:
**(0, 0) and (3.2, 0)**
\[
-5x^2 + 16x = 0
\]
We can factor out \(x\):
\[
x(-5x + 16) = 0
\]
This gives us two equations to solve:
1. \(x = 0\)
2. \(-5x + 16 = 0\)
Now, let's solve the second equation:
\(-5x + 16 = 0\)
Rearranging gives:
\(-5x = -16\)
Dividing both sides by -5:
\[
x = \frac{16}{5} = 3.2
\]
So the zeros of the function are:
\[
x = 0 \quad \text{and} \quad x = 3.2
\]
In coordinate form, the zeros are (0, 0) and (3.2, 0).
Thus, the correct response is:
**(0, 0) and (3.2, 0)**
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