Question
Determine the zero(s) of the quadratic function y=−5x^2+16x
(1 point)
Responses
(-3.2, 0)
(-3.2, 0)
There are no zeros.
There are no zeros.
(0, 0) and (3.2, 0)
(0, 0) and (3.2, 0)
(0,5) and (0, 16)
(1 point)
Responses
(-3.2, 0)
(-3.2, 0)
There are no zeros.
There are no zeros.
(0, 0) and (3.2, 0)
(0, 0) and (3.2, 0)
(0,5) and (0, 16)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the zeros of the quadratic function \( y = -5x^2 + 16x \), we set \( y \) equal to zero:
\[
0 = -5x^2 + 16x
\]
Next, we can factor the equation:
\[
0 = x(-5x + 16)
\]
Setting each factor to zero gives:
1. \( x = 0 \)
2. \( -5x + 16 = 0 \)
From the second equation, we solve for \( x \):
\[
-5x + 16 = 0 \\
5x = 16 \\
x = \frac{16}{5} = 3.2
\]
Thus, the zeros of the function are \( x = 0 \) and \( x = 3.2 \).
The corresponding points where \( y = 0 \) are:
- \( (0, 0) \)
- \( (3.2, 0) \)
Therefore, the correct response is:
\((0, 0)\) and \((3.2, 0)\)
\[
0 = -5x^2 + 16x
\]
Next, we can factor the equation:
\[
0 = x(-5x + 16)
\]
Setting each factor to zero gives:
1. \( x = 0 \)
2. \( -5x + 16 = 0 \)
From the second equation, we solve for \( x \):
\[
-5x + 16 = 0 \\
5x = 16 \\
x = \frac{16}{5} = 3.2
\]
Thus, the zeros of the function are \( x = 0 \) and \( x = 3.2 \).
The corresponding points where \( y = 0 \) are:
- \( (0, 0) \)
- \( (3.2, 0) \)
Therefore, the correct response is:
\((0, 0)\) and \((3.2, 0)\)
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