To find the zeros of the quadratic function \( y = -5x^2 + 16x \), we set \( y \) equal to zero:
\[ 0 = -5x^2 + 16x \]
Next, we can factor the equation:
\[ 0 = x(-5x + 16) \]
Setting each factor to zero gives:
- \( x = 0 \)
- \( -5x + 16 = 0 \)
From the second equation, we solve for \( x \):
\[ -5x + 16 = 0 \ 5x = 16 \ x = \frac{16}{5} = 3.2 \]
Thus, the zeros of the function are \( x = 0 \) and \( x = 3.2 \).
The corresponding points where \( y = 0 \) are:
- \( (0, 0) \)
- \( (3.2, 0) \)
Therefore, the correct response is:
\((0, 0)\) and \((3.2, 0)\)