ok, I guess you didn't like the volume ratio solution, so here is the general algebraic solution.
You have two solutions, one at 19% acid, and the water at 0% acid.
If you use x ml of water, the final solution will have (x+50)ml volume.
The amounts of acid in each component solution must add up to the amount of acid in the final solution. That is,
0.698*50 + 0.00*x = 0.19(x+50)
solve that and you get
x = 183.68
Determine the volume of diluted nitric acid D1.11g/ml, 19% hn03. That can be prepared by diluting with water 50ml of conc hn03 d= 1.42g/ml, 69.8%
I do not still understand how 183.68ml
I want you clear explain step by step for me.
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