Determine the volume of 0.150 M NaOH that neutralizes 0.188 g of a diprotic acid having a molar mass of 152.2 g/mol?

Answer 1

Let's let the diportic acid be H2A.
The equation is
H2A + 2NaOH ==> Na2A + 2H2O
moles H2A = 0.188/152.2
Convert moles H2A to moles NaOH using the coefficients in the balanced equation.
Now convert moles NaOH to L using M = moles/L.