Determine the volume (in mL) of a 0.184 M CaCl2 solution that would be required to obtain 73.4 g of CaCl2.
1 answer
0.184 x molar mass = grams CaCl2/L = 20.42 grams. So if you have 20.42 g in 1000 mL, how many mL will it take to obtain 73.4g.