geez - why say everything twice? So annoying!
Assuming points ABCD are in order, and that AED is divided into three equal parts, then
AEC=AEB+BEC
7x+16 = 3x+14 + BEC
BEC = 4x+2
CED=AEB and AEC=2AEB
7x+16 = 2(4x+2)
x = 12
2y+3x = 4x+2
2y=x+2
y = 7
Determine the values for x and y if \angle AEB=3x+14,\angle AEC=7x+16,∠AEB=3x+14,∠AEC=7x+16, and \angle CED=2y+3x∠CED=2y+3x
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