Determine the theoretical percent composition of water in bluestone

Answer 1

To determine the theoretical percent composition of water in bluestone (CuSO4·5H2O), we need to consider the molar mass of the compound.

The molar mass of CuSO4·5H2O can be calculated as follows:

Copper (Cu): 1 atom x 63.5 g/mol = 63.5 g/mol
Sulfur (S): 1 atom x 32.1 g/mol = 32.1 g/mol
Oxygen (O): 4 atoms x 16.0 g/mol = 64.0 g/mol
Hydrogen (H): 10 atoms x 1.0 g/mol = 10.0 g/mol

Total molar mass = 63.5 + 32.1 + 64.0 + 10.0 = 169.6 g/mol

Now, we need to calculate the mass of water (5H2O) in the compound:

Water (H2O): 5 molecules x 18.0 g/mol = 90.0 g/mol

The percent composition of water in bluestone can be calculated as:

(90.0 g/mol / 169.6 g/mol) x 100% = 53.0%

Therefore, the theoretical percent composition of water in bluestone is 53.0%.