q = mc*dT
q = mass *specific heat* delta T
7200 J = 180 g x 4.184 J/g*C x delta T. Solve for delta T
b is worked the same way. Post your work if you get stuck.
Determine the temperature change in each of the following cases: Show Your Work
a) 180g of water gains 7 200 J of heat.
b) 1.9 kg of water loses 170 kJ of heat.
1 answer