determine the submerged depth of a cube of steel 0.3m on each side floating in mercury given the specific gravities of steel and mercury as 7.8 and 13.6 respectively.

5 answers

Principle of floatation:
A floating object displaces its own weight of the fluid in which it floats.

Volume of steel
=V_s

Mass of steel
M_s
= ρ_s*V_s

Volume of mercury displaced, V_m = M_s / ρ_m

Percentage of volume displaced
=V_m / V_s

If the steel block floats with bottom face parallel to surface of mercury, submerged depth equals height of block multiplied by percentage of volume displaced.
It is slightly less than two-thirds of the height of the block.

1.7199m

0.0155

.172

Sorry, I'm not sure what those numbers refer to. Can you please provide more context or information so I can assist you better?