To solve the equation \(-3x + 7 = 10\):
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Subtract 7 from both sides: \[ -3x = 10 - 7 \] \[ -3x = 3 \]
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Divide both sides by -3: \[ x = \frac{3}{-3} = -1 \]
Now, let's solve the second equation \(3x - 9 = 0\):
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Add 9 to both sides: \[ 3x = 9 \]
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Divide both sides by 3: \[ x = \frac{9}{3} = 3 \]
The solutions to the equations are \(x = -1\) and \(x = 3\). Since the original problem uses "or," the overall solution set is: \[ { -1, 3 } \]