what's the trouble? just use the product rule to get
f'(x) = 5e^x + 5xe^x = 5e^x(1+x)
f'(2) = 10e^2
Determine the slope of the tangent to the function f(x)=5xe^x at the point with x-coordinate x=2
a) -1/5
b) 10e^2
c) 15e^2
d) -5e^2
1 answer
1 answer