Asked by Tom
Determine the sample size necessary to estimate a population proportion to within .03 with 90% confidence assuming you have no knowledge of the approximate value of the sample proportion.
Answers
Answered by
MathGuru
Try this formula:
n = [(z-value)^2 * p * q]/E^2
Note: n = sample size needed; .5 for p and .5 for q are used if no value is stated in the problem. E = maximum error, which is .03 in the problem. Z-value is found using a z-table to represent 90% interval. Round final result to next highest whole number.
Also: ^2 means squared and * means to multiply.
I hope this will help get you started.
n = [(z-value)^2 * p * q]/E^2
Note: n = sample size needed; .5 for p and .5 for q are used if no value is stated in the problem. E = maximum error, which is .03 in the problem. Z-value is found using a z-table to represent 90% interval. Round final result to next highest whole number.
Also: ^2 means squared and * means to multiply.
I hope this will help get you started.
Answered by
mia
n = [(z-value)^2 * p * q]/E^2
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