To find the resulting polynomial \( f(x) \cdot g(x) \) where
\[ f(x) = 2x + 6 \]
and
\[ g(x) = 6x^2 - x + 10, \]
we will multiply these two polynomials together.
Step 1: Set up the multiplication
First, we write down the expression:
\[ f(x) \cdot g(x) = (2x + 6)(6x^2 - x + 10) \]
Step 2: Distribute each term in \(f(x)\)
We will distribute each term in \( f(x) \) over \( g(x) \):
-
Multiply \( 2x \) by each term in \( g(x) \):
- \( 2x \cdot 6x^2 = 12x^3 \)
- \( 2x \cdot (-x) = -2x^2 \)
- \( 2x \cdot 10 = 20x \)
-
Multiply \( 6 \) by each term in \( g(x) \):
- \( 6 \cdot 6x^2 = 36x^2 \)
- \( 6 \cdot (-x) = -6x \)
- \( 6 \cdot 10 = 60 \)
Step 3: Combine the results
Now, we combine all these results:
\[ 12x^3 + (-2x^2) + 20x + 36x^2 + (-6x) + 60 \]
Step 4: Combine like terms
Next, we combine the like terms:
- The \( x^3 \) term: \( 12x^3 \)
- The \( x^2 \) terms: \( -2x^2 + 36x^2 = 34x^2 \)
- The \( x \) terms: \( 20x - 6x = 14x \)
- The constant term: \( 60 \)
Resulting Polynomial
So, the resulting polynomial is:
\[ f(x) \cdot g(x) = 12x^3 + 34x^2 + 14x + 60 \]
Thus, the answer is:
\[ \boxed{12x^3 + 34x^2 + 14x + 60} \]