Determine the required nominal diameter of a threaded steel rod to carry an axial load of 16,000 pounds in tension if the tensile stress of 20,000 psi is permitted.

Answer 1

Find the area...

Area*20kpsi=16kpouds
area= 800 in^2
PI*(Diameter/2)^2=800
solve for diameter in inches.

Answer 2

Thanks bob mind helping me with one more? The questions all ready posted, same subject.