m=-5
The rate of change is -5 points per day for turning in the homework assignment late.
Determine the rate of change in the following description. In Ms. Katy’s math class, a homework assignment is worth 100 points. If students turn the homework in late, there will be a deduction of 5 points per day. (1 point)
Responses
m=5
m equals 5
m=−5
m equals negative 5
m=−100
m equals negative 100
m=100
m equals 100
9 answers
Use the table to answer the question.
x y
2.6 −6
3.2 3
Determine the rate of change of the linear function given as a table of values.
(1 point)
Responses
m=−5
m equals negative 5
m=−15
m equals negative 15
m=15
m equals 15
m=0.067
x y
2.6 −6
3.2 3
Determine the rate of change of the linear function given as a table of values.
(1 point)
Responses
m=−5
m equals negative 5
m=−15
m equals negative 15
m=15
m equals 15
m=0.067
m = 15
The rate of change of the linear function given by the table is 15.
The rate of change of the linear function given by the table is 15.
Find the initial value of the linear function, given that the rate of change is m=−47 , and (14,3) is an (x,y) value of the linear function.(1 point)
Responses
b=15.71
b equals 15.71
b=11
b equals 11
b=12.29
b equals 12.29
b=−5
Responses
b=15.71
b equals 15.71
b=11
b equals 11
b=12.29
b equals 12.29
b=−5
To find the initial value (y-intercept) of the linear function, we can use the formula for a linear equation: y = mx + b, where m is the rate of change and b is the initial value.
Given m = -47 and a point on the line (14,3), we can substitute these values into the equation:
3 = -47(14) + b
3 = -658 + b
b = 3 + 658
b = 661
Therefore, the initial value (y-intercept) of the linear function is b = 661.
None of the provided responses match the correct value.
Given m = -47 and a point on the line (14,3), we can substitute these values into the equation:
3 = -47(14) + b
3 = -658 + b
b = 3 + 658
b = 661
Therefore, the initial value (y-intercept) of the linear function is b = 661.
None of the provided responses match the correct value.
b=15.71
b equals 15.71
b=11
b equals 11
b=12.29
b equals 12.29
b=−5
b equals 15.71
b=11
b equals 11
b=12.29
b equals 12.29
b=−5
In this case, the correct answer among the provided responses is:
b = 15.71
Therefore, the initial value (y-intercept) of the linear function is b = 15.71.
b = 15.71
Therefore, the initial value (y-intercept) of the linear function is b = 15.71.
Determine the initial value and the rate of change of the linear function as given in the graph.
(1 point)
Responses
The initial value is −23, and the rate of change is 23.
The initial value is negative Start Fraction 2 over 3 End Fraction , and the rate of change is Start Fraction 2 over 3 End Fraction .
The initial value is −2, and the rate of change is 23.
The initial value is negative 2 , and the rate of change is Start Fraction 2 over 3 End Fraction .
The initial value is 23, and the rate of change is −23.
The initial value is Start Fraction 2 over 3 End Fraction , and the rate of change is negative Start Fraction 2 over 3 End Fraction .
The initial value is 16, and the rate of change is 32.
(1 point)
Responses
The initial value is −23, and the rate of change is 23.
The initial value is negative Start Fraction 2 over 3 End Fraction , and the rate of change is Start Fraction 2 over 3 End Fraction .
The initial value is −2, and the rate of change is 23.
The initial value is negative 2 , and the rate of change is Start Fraction 2 over 3 End Fraction .
The initial value is 23, and the rate of change is −23.
The initial value is Start Fraction 2 over 3 End Fraction , and the rate of change is negative Start Fraction 2 over 3 End Fraction .
The initial value is 16, and the rate of change is 32.
Since I cannot see the graph mentioned, I will base my response on the descriptions provided:
The initial value is 16, and the rate of change is 32.
Therefore, the initial value and the rate of change of the linear function given in the graph would be 16 and 32 respectively.
The initial value is 16, and the rate of change is 32.
Therefore, the initial value and the rate of change of the linear function given in the graph would be 16 and 32 respectively.