Asked by chichi

Determine the quarter points.
y=cos(x−5π/2)

​(Type an exact​ answer, using π as needed. Use integers or fractions for any numbers in the​ expression.)

- Please show step by step work. Show how you're getting the numbers/answers because I want to learn it. Thank You.
Answered by Reiny
y=cos(x−5π/2)
amplitude = 1
period = 2π

If we had the simple curve y = cos x
the quarter points would be
(0,1) , (π/2, 0) , (π, -1), (3π/2 , 0) , and repeating at (2π, 1)
but we shifted our basic cosine curve 5π/2 units to the right, so our points are:

(0 + 5π/2, 1), (π/2 + 5π/2, 0) , (π + 5π/2, -1) .....
or
(5π/2, 1) , (3π , 0) , (7π/2, -1) , ....

remember that the period is 2π
so we can add or subtract 2π to get more or other points

(5π/2 - 2π,1) , (3π - 2π, 0) , (7π/2, -1) , ....

(π/2, 1) , (π,0), (3π/2 , -1), ...

ahhhh , but that is the same as y = sin(x)


check:
http://www.wolframalpha.com/input/?i=y%3Dcos(x%E2%88%925%CF%80%2F2)
Answered by chichi
THANK YOU SOOO MUCH REINY!! GOD BLESS YOU. YOU'RE AMAZING!
Answered by Damon
ahhhh , but that is the same as y = sin(x)

:)
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