f(x) = a(x+3)^2 - 13
since f(0) = -4,
-4 = 9a-13
a = 1
f(x) = (x+3)^2 - 13
Determine the quadratic function f whose graph is given.
The vertex is (-3,-13) and the y-intercept is -4
f(x)=
1 answer
The vertex is (-3,-13) and the y-intercept is -4
f(x)=
1 answer