For a vertex of (1,-3) the equation is
Y= a(x-1)^2 - 3
But (0,-2)lies on it, so
-2 = a(0-1)^2 -3
1 = a
Y = (x-1)^2 - 3
determine the quadratic function f whose graph is given.
the vertex is (1,-3)
y intercept is -2
please show work so i can see how this is done, thank you!
2 answers
Find the equation of the quadratic Functions whose graph is a parabola the points (-2,19), (3,14) and (4,25)