The pH of salts is determined by the hydrolysis of the salt. In the case of NH4Cl, the NH4^+ is hydrolyzed because it is a stronger acid than H2O (the NH4^+ donates a H^+ to H2O).
.........NH4^+ + H2O ==> H3O^+ + NH3
.........0.1...............0......0
change....-x...............x......x
equil....0.1-x.............x......x
Ka for NH4^+ = (Kw/Kb for NH3) = (H3O^+)(NH3)/(NH4+)
Substitute from the ICE chart and solve for x which is H3O^+, and convert that to pH.
Determine the pH of each solution:
(a) 0.10 M NH4Cl
can someone show me how to do this one so i have the idea of how to do the rest. thanks!
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