Use the Henderson-Hasselbalch equation.
You have (acid). Look to see how much of the sodium acetate was formed and calculate concn of that. Plug in HH equation and pH comes out as the answer.
Determine the pH of a solution of 12.00 mL of 0.2 M acetic acid with 10 mL of a 0.025M NaOH? (Ka = 1.8E–5)
I've calculated my excess moles of acetic to be .00215. Total volume being .022L.
Where do I go from here? Thanks!
3 answers
4.18
I don't think so.
0.00215 is right and 0.022 is right. mols sodium acetate should be 0.00025
If you will post your set up I'll find the error.
0.00215 is right and 0.022 is right. mols sodium acetate should be 0.00025
If you will post your set up I'll find the error.