To determine the pH of a NaOH solution, we first need to calculate the pOH of the solution using the concentration of NaOH.
Given:
[NaOH] = 2.2 x 10^-11 M
Since NaOH is a strong base, it will fully dissociate in water into Na+ and OH- ions. Therefore, the concentration of OH- ions in the solution is equal to the concentration of NaOH.
pOH = -log[OH-] = -log(2.2 x 10^-11) = 10.66
Since pH + pOH = 14, we can now calculate the pH:
pH = 14 - pOH = 14 - 10.66 = 3.34
Therefore, the pH of a 2.2 x 10^-11 M NaOH solution is 3.34.
Determine the pH of a 2.2 x 10-11 M NaOH solution.
1 answer