Determine the ordered pair that lies on the unit circle corresponding to csc(5π/6). Thank you.

3 answers

The wording of your question makes no sense to me.
Do you want csc(5π/6) as found on the unit circle?
We have an ordered pair associated with (5π/6) , not csc(5π/6)

I strongly suggest you print out one of the many unit circle diagrams available.
Here is one of them
https://www.google.ca/search?q=unit+circle+trigonometry&rlz=1C5CHFA_enCA690CA690&espv=2&biw=1660&bih=856&tbm=isch&imgil=b6OyxY_TLZ5-KM%253A%253BrinOamBJgRKAGM%253Bhttp%25253A%25252F%25252Fmathematica.stackexchange.com%25252Fquestions%25252F2456%25252Fgenerate-a-unit-circle-trigonometry&source=iu&pf=m&fir=b6OyxY_TLZ5-KM%253A%252CrinOamBJgRKAGM%252C_&usg=__HP98aavLGtFPfphMrS_Wm9xhprU%3D&ved=0ahUKEwiuwt603brOAhWLWxQKHTuoDDAQyjcIKA&ei=4iatV67JJou3UbvQsoAD#imgrc=b6OyxY_TLZ5-KM%3A

All ordered pairs are of the form (cosØ, sinØ)
since sin (5π/6) = 1/2
csc (5π/6) = 2
This is how the question appears.

Determine the ordered pair that lies on the unit circle corresponding to t=5pi/6. I'm sorry for the confusion.
That's not what you had originally.
Glad you changed it, now my solution should make sense to you.