Determine the number of solutions to this system of linear equations (0, 1, infinity):

y = 7x + 8
-7 + y = -8
(1 point)
This system of linear equations has

1 answer

Let's analyze the given system of linear equations:

  1. The first equation is: \[ y = 7x + 8 \]

  2. The second equation simplifies as follows: \[ -7 + y = -8 \] Adding 7 to both sides: \[ y = -1 \]

Now we have the system:

  1. \( y = 7x + 8 \)
  2. \( y = -1 \)

To find the intersection of these two equations, we can set them equal to each other: \[ 7x + 8 = -1 \]

Solving for \( x \): \[ 7x = -1 - 8 \] \[ 7x = -9 \] \[ x = -\frac{9}{7} \]

Now substituting \( x = -\frac{9}{7} \) back into either equation to find \( y \): Using \( y = -1 \): \[ y = -1 \]

Thus, we have a single solution: \[ \left(-\frac{9}{7}, -1\right) \]

This means that the system of linear equations has exactly one solution.

Thus, the answer is 1.