To determine the number of solutions to the given system of linear equations:
- \( y = x + 5 \)
- \( y = -x + 5 \)
We can analyze the equations:
- The first equation \( y = x + 5 \) represents a line with a slope of 1, which means it rises as \( x \) increases.
- The second equation \( y = -x + 5 \) represents a line with a slope of -1, which means it falls as \( x \) increases.
To find the point of intersection, we can set the two equations equal to each other:
\[ x + 5 = -x + 5 \]
Now, solve for \( x \):
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Add \( x \) to both sides: \[ 2x + 5 = 5 \]
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Subtract 5 from both sides: \[ 2x = 0 \]
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Divide by 2: \[ x = 0 \]
Now substitute \( x = 0 \) back into one of the original equations to find \( y \):
Using the first equation: \[ y = 0 + 5 = 5 \]
Thus, the point of intersection is \( (0, 5) \), which means the two lines intersect at a single point.
Therefore, the number of solutions to the system of equations is:
1