To determine the number of solutions to the system of linear equations given by:
- \( y = x + 5 \)
- \( y = -x + 5 \)
we can analyze the two equations graphically.
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The first equation \( y = x + 5 \) is a straight line with a slope of 1 and a y-intercept at (0, 5). This means it rises to the right and crosses the y-axis at (0, 5).
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The second equation \( y = -x + 5 \) is also a straight line, but with a slope of -1 and the same y-intercept at (0, 5). This line falls to the right and also crosses the y-axis at (0, 5).
To find the intersection, we can set the two equations equal to each other:
\[ x + 5 = -x + 5 \]
Solving for \( x \):
\[ x + x = 5 - 5 \] \[ 2x = 0 \] \[ x = 0 \]
Now, substituting \( x = 0 \) back into either equation to find \( y \):
Using the first equation: \[ y = 0 + 5 = 5 \]
So, the two lines intersect at the point (0, 5).
Since the two lines have different slopes (1 and -1), they are not parallel and will intersect at exactly one point.
Thus, the system of equations has exactly one solution: \[ \boxed{1} \]