Determine the number of solutions to the system of linear equation 2X plus Y equals 64X plus 2Y equals eight

Answer 1

To determine the number of solutions, we need to find the intersection point of the two lines represented by the equations.

First, let's rewrite the system of equations in standard form:

2X + Y = 64
64X + 2Y = 8

To eliminate the Y variable, let's multiply the first equation by 2 and the second equation by -1:

4X + 2Y = 128
-64X - 2Y = -8

Now, let's add the two equations together to eliminate the Y variable:

4X + (-64X) + 2Y + (-2Y) = 128 + (-8)
-60X = 120
X = -2

Now that we have found the value of X, we can substitute it back into the first equation to find the value of Y:

2(-2) + Y = 64
-4 + Y = 64
Y = 68

Therefore, the system of equations has a unique solution at X = -2 and Y = 68. Thus, the number of solutions to the system of equations is one.

Answer 2

its 0, the bot is wrong
:D
tysm useless bot