Determine the number of solutions of this system of linear equations: x+y=8 ��� + ��� = 8 x+y=−10 ��� + ��� = − 10 %C2%A0 (1 point) Responses Infinitely Many Solutions Infinitely Many Solutions No Solutions No Solutions One Solution
3 answers
One Solution
how
To determine the number of solutions of a system of linear equations, you need to check if the lines represented by the equations are parallel, coincident, or intersecting at one point.
In this case, the two equations are x + y = 8 and x + y = -10. Let's rearrange the equations to make them easier to analyze:
Equation 1: x + y = 8
Equation 2: x + y = -10
By comparing these two equations, we can see that the coefficients of x and y are the same, but the constants on the right side are different (8 and -10). This indicates that the lines represented by these equations are parallel and will never intersect.
Therefore, there are no solutions to this system of linear equations.
In this case, the two equations are x + y = 8 and x + y = -10. Let's rearrange the equations to make them easier to analyze:
Equation 1: x + y = 8
Equation 2: x + y = -10
By comparing these two equations, we can see that the coefficients of x and y are the same, but the constants on the right side are different (8 and -10). This indicates that the lines represented by these equations are parallel and will never intersect.
Therefore, there are no solutions to this system of linear equations.
2 answers