To find a number greater than 50 but less than 65 that is divisible by both 3 and 9, we first note that any number divisible by 9 is also divisible by 3. Therefore, we need to check which of the provided numbers (51, 54, 60, 67) are divisible by 9.
We will check divisibility by 9 by calculating each number divided by 9:
- 51: \( 51 \div 9 = 5.67 \) (not an integer)
- 54: \( 54 \div 9 = 6 \) (integer, divisible by 9)
- 60: \( 60 \div 9 = 6.67 \) (not an integer)
- 67: \( 67 \div 9 = 7.44 \) (not an integer)
Among these, only 54 is divisible by both 3 and 9.
Thus, the answer is 54.
1 answer